x^2+30X-3300=0

Solution for x^2+30X-3300=0 equation:

x^2+30x-3300=0

a = 1; b = 30; c = -3300;
Δ = b2-4ac
Δ = 302-4·1·(-3300)
Δ = 14100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{14100}=\sqrt{100*141}=\sqrt{100}*\sqrt{141}=10\sqrt{141}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-10\sqrt{141}}{2*1}=\frac{-30-10\sqrt{141}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+10\sqrt{141}}{2*1}=\frac{-30+10\sqrt{141}}{2}
$